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2x^2-7.9x+4=0
a = 2; b = -7.9; c = +4;
Δ = b2-4ac
Δ = -7.92-4·2·4
Δ = 30.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.9)-\sqrt{30.41}}{2*2}=\frac{7.9-\sqrt{30.41}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.9)+\sqrt{30.41}}{2*2}=\frac{7.9+\sqrt{30.41}}{4} $
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